In the chapter on grammars, we have seen how to use *grammars* for very effective and efficient testing. In this chapter, we refine the previous string-based algorithm into a tree-based algorithm, which is much faster and allows for much more control over the production of fuzz inputs.

In the previous chapter, we have introduced the `simple_grammar_fuzzer()`

function which takes a grammar and automatically produces a syntactically valid string from it. However, `simple_grammar_fuzzer()`

is just what its name suggests – simple. To illustrate the problem, let us get back to the `expr_grammar`

we created from `EXPR_GRAMMAR_BNF`

in the chapter on grammars:

In [4]:

```
expr_grammar = convert_ebnf_grammar(EXPR_EBNF_GRAMMAR)
expr_grammar
```

Out[4]:

{'<start>': ['<expr>'], '<expr>': ['<term> + <expr>', '<term> - <expr>', '<term>'], '<term>': ['<factor> * <term>', '<factor> / <term>', '<factor>'], '<factor>': ['<sign-1><factor>', '(<expr>)', '<integer><symbol-1>'], '<sign>': ['+', '-'], '<integer>': ['<digit-1>'], '<digit>': ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9'], '<symbol>': ['.<integer>'], '<sign-1>': ['', '<sign>'], '<symbol-1>': ['', '<symbol>'], '<digit-1>': ['<digit>', '<digit><digit-1>']}

`expr_grammar`

has an interesting property. If we feed it into `simple_grammar_fuzzer()`

, the function gets stuck in an infinite expansion:

In [6]:

```
with ExpectTimeout(1):
simple_grammar_fuzzer(grammar=expr_grammar, max_nonterminals=3)
```

Why is that so? The problem is in this rule:

In [7]:

```
expr_grammar['<factor>']
```

Out[7]:

['<sign-1><factor>', '(<expr>)', '<integer><symbol-1>']

`(expr)`

increases the number of symbols, even if only temporary. Since we place a hard limit on the number of symbols to expand, the only choice left for expanding `<factor>`

is `(<expr>)`

, which leads to an infinite addition of parentheses.

The problem of potentially infinite expansion is only one of the problems with `simple_grammar_fuzzer()`

. More problems include:

*It is inefficient*. With each iteration, this fuzzer would go search the string produced so far for symbols to expand. This becomes inefficient as the production string grows.*It is hard to control.*Even while limiting the number of symbols, it is still possible to obtain very long strings – and even infinitely long ones, as discussed above.

Let us illustrate both problems by plotting the time required for strings of different lengths.

In [12]:

```
trials = 50
xs = []
ys = []
for i in range(trials):
with Timer() as t:
s = simple_grammar_fuzzer(EXPR_GRAMMAR, max_nonterminals=15)
xs.append(len(s))
ys.append(t.elapsed_time())
print(i, end=" ")
print()
```

In [13]:

```
average_time = sum(ys) / trials
print("Average time:", average_time)
```

Average time: 0.19074946056032785

In [14]:

```
%matplotlib inline
import matplotlib.pyplot as plt
plt.scatter(xs, ys)
plt.title('Time required for generating an output')
```

Out[14]:

Text(0.5,1,'Time required for generating an output')

To address these problems, we need a *smarter algorithm* – one that is more efficient, that gets us better control over expansions, and that is able to foresee in `expr_grammar`

that the `(expr)`

alternative yields a potentially infinite expansion, in contrast to the other two.

To both obtain a more efficient algorithm *and* exercise better control over expansions, we will use a special representation for the strings that our grammar produces. The general idea is to use a *tree* structure that will be subsequently expanded – a so-called *derivation tree*. This representation allows us to always keep track of our expansion status – answering questions such as which elements have been expanded into which others, and which symbols still need to be expanded. Furthermore, adding new elements to a tree is far more efficient than replacing strings again and again.

*parse tree* or *concrete syntax tree*) consists of *nodes* which have other nodes (called *child nodes*) as their *children*. The tree starts with one node that has no parent; this is called the *root node*; a node without children is called a *leaf*.

The grammar expansion process with derivation trees is illustrated in the following steps, using the arithmetic grammar from
the chapter on grammars. We start with a single node as root of the tree, representing the *start symbol* – in our case `<start>`

.

In [17]:

```
tree
```

Out[17]:

To expand the tree, we traverse it, searching for a nonterminal symbol $S$ without children. $S$ thus is a symbol that still has to be expanded. We then chose an expansion for $S$ from the grammar. Then, we add the expansion as a new child of $S$. For our start symbol `<start>`

, the only expansion is `<expr>`

, so we add it as a child.

In [19]:

```
tree
```

Out[19]:

To construct the produced string from a derivation tree, we traverse the tree in order and collect the symbols at the leaves of the tree. In the case above, we obtain the string `"<expr>"`

.

To further expand the tree, we choose another symbol to expand, and add its expansion as new children. This would get us the `<expr>`

symbol, which gets expanded into `<expr> + <term>`

, adding three children.

In [21]:

```
tree
```

Out[21]:

We repeat the expansion until there are no symbols left to expand:

In [23]:

```
tree
```

Out[23]:

`2 + 2`

. In contrast to the string alone, though, the derivation tree records *the entire structure* (and production history, or *derivation* history) of the produced string. It also allows for simple comparison and manipulation – say, replacing one subtree (substructure) against another.

To represent a derivation tree in Python, we use the following format. A node is a pair

```
(SYMBOL_NAME, CHILDREN)
```

where `SYMBOL_NAME`

is a string representing the node (i.e. `"<start>"`

or `"+"`

) and `CHILDREN`

is a list of children nodes.

`CHILDREN`

can take some special values:

`None`

as a placeholder for future expansion. This means that the node is a*nonterminal symbol*that should be expanded further.`[]`

(i.e., the empty list) to indicate*no*children. This means that the node is a*terminal symbol*that can no longer be expanded.

Let us take a very simple derivation tree, representing the intermediate step `<expr> + <term>`

, above.

In [24]:

```
derivation_tree = ("<start>",
[("<expr>",
[("<expr>", None),
(" + ", []),
("<term>", None)]
)])
```

To better understand the structure of this tree, let us introduce a function that visualizes this tree. We use the `dot`

drawing program from the `graphviz`

package algorithmically, traversing the above structure. (Unless you're deeply interested in tree visualization, you can directly skip to the example below.)

`derivation_tree`

, it is in our interest to generalize the visualization procedure. In particular, it would be helpful if our method `display_tree()`

can display *any* tree like data structure. To enable this, we define a helper method `extract_node()`

that extract the current symbol and children from a given data structure. The default implementation simply extracts the symbol, children, and annotation from any `derivation_tree`

node.

In [29]:

```
def extract_node(node, id):
symbol, children, *annotation = node
return symbol, children, ''.join(str(a) for a in annotation)
```

While visualizing a tree, it is often useful to display certain nodes differently. For example, it is sometimes useful to distinguish between non-processed nodes and processed nodes. We define a helper procedure `default_node_attr()`

that provides the basic display, which can be customized by the user.

In [30]:

```
def default_node_attr(dot, nid, symbol, ann):
dot.node(repr(nid), dot_escape(unicode_escape(symbol)))
```

`default_edge_attr()`

as a helper procedure that can be customized by the user.

In [31]:

```
def default_edge_attr(dot, start_node, stop_node):
dot.edge(repr(start_node), repr(stop_node))
```

While visualizing a tree, one may sometimes wish to change the appearance of the tree. For example, it is sometimes easier to view the tree if it was laid out left to right rather than top to bottom. We define another helper procedure `default_graph_attr()`

for that.

In [32]:

```
def default_graph_attr(dot):
dot.attr('node', shape='plain')
```

`display_tree()`

that accepts these four functions `extract_node()`

, `default_edge_attr()`

, `default_node_attr()`

and `default_graph_attr()`

and uses them to display the tree.

In [33]:

```
def display_tree(derivation_tree,
log=False,
extract_node=extract_node,
node_attr=default_node_attr,
edge_attr=default_edge_attr,
graph_attr=default_graph_attr):
counter = 0
def traverse_tree(dot, tree, id=0):
(symbol, children, annotation) = extract_node(tree, id)
node_attr(dot, id, symbol, annotation)
if children:
for child in children:
nonlocal counter
counter += 1
child_id = counter
edge_attr(dot, id, child_id)
traverse_tree(dot, child, child_id)
dot = Digraph(comment="Derivation Tree")
graph_attr(dot)
traverse_tree(dot, derivation_tree)
if log:
print(dot)
display(dot)
```

This is what our tree visualizes into:

In [34]:

```
display_tree(derivation_tree)
```

`display_annotated_tree()`

that displays an annotated tree structure, and lays the graph out left to right.

In [35]:

```
def display_annotated_tree(tree, a_nodes, a_edges, log=False):
def graph_attr(dot):
dot.attr('node', shape='plain')
dot.graph_attr['rankdir'] = 'LR'
def annotate_node(dot, nid, symbol, ann):
if nid in a_nodes:
dot.node(repr(nid), "%s (%s)" % (dot_escape(unicode_escape(symbol)), a_nodes[nid]))
else:
dot.node(repr(nid), dot_escape(unicode_escape(symbol)))
def annotate_edge(dot, start_node, stop_node):
if (start_node, stop_node) in a_edges:
dot.edge(repr(start_node), repr(stop_node),
a_edges[(start_node, stop_node)])
else:
dot.edge(repr(start_node), repr(stop_node))
display_tree(tree, log=log,
node_attr=annotate_node,
edge_attr=annotate_edge,
graph_attr=graph_attr)
```

In [36]:

```
display_annotated_tree(derivation_tree, {3: 'plus'}, {(1, 3): 'op'}, log=False)
```

`all_terminals()`

function comes in handy:

In [37]:

```
def all_terminals(tree):
(symbol, children) = tree
if children is None:
# This is a nonterminal symbol not expanded yet
return symbol
if len(children) == 0:
# This is a terminal symbol
return symbol
# This is an expanded symbol:
# Concatenate all terminal symbols from all children
return ''.join([all_terminals(c) for c in children])
```

In [38]:

```
all_terminals(derivation_tree)
```

Out[38]:

'<expr> + <term>'

The `all_terminals()`

function returns the string representation of all leaf nodes. However, some of these leaf nodes may be due to nonterminals deriving empty strings. For these, we want to return the empty string. Hence, we define a new function `tree_to_string()`

to retrieve the original string back from a tree like structure.

In [39]:

```
def tree_to_string(tree):
symbol, children, *_ = tree
if children:
return ''.join(tree_to_string(c) for c in children)
else:
return '' if is_nonterminal(symbol) else symbol
```

In [40]:

```
tree_to_string(derivation_tree)
```

Out[40]:

' + '

`derivation_tree`

, above), and expands all these symbols one after the other. As with earlier fuzzers, we create a special subclass of `Fuzzer`

– in this case, `GrammarFuzzer`

. A `GrammarFuzzer`

gets a grammar and a start symbol; the other parameters will be used later to further control creation and to support debugging.

In [42]:

```
class GrammarFuzzer(Fuzzer):
def __init__(self, grammar, start_symbol=START_SYMBOL,
min_nonterminals=0, max_nonterminals=10, disp=False, log=False):
self.grammar = grammar
self.start_symbol = start_symbol
self.min_nonterminals = min_nonterminals
self.max_nonterminals = max_nonterminals
self.disp = disp
self.log = log
self.check_grammar()
```

In the following, we will add further methods to `GrammarFuzzer`

, using the hack already introduced for the `MutationFuzzer`

class. The construct

```
class GrammarFuzzer(GrammarFuzzer):
def new_method(self, args):
pass
```

allows us to add a new method `new_method()`

to the `GrammarFuzzer`

class. (Actually, we get a new `GrammarFuzzer`

class that extends the old one, but for all our purposes, this does not matter.)

Using this hack, let us define a helper method `check_grammar()`

that checks the given grammar for consistency:

In [43]:

```
class GrammarFuzzer(GrammarFuzzer):
def check_grammar(self):
assert self.start_symbol in self.grammar
assert is_valid_grammar(
self.grammar,
start_symbol=self.start_symbol,
supported_opts=self.supported_opts())
def supported_opts(self):
return set()
```

Let us now define a helper method `init_tree()`

that constructs a tree with just the start symbol:

In [44]:

```
class GrammarFuzzer(GrammarFuzzer):
def init_tree(self):
return (self.start_symbol, None)
```

In [45]:

```
f = GrammarFuzzer(EXPR_GRAMMAR)
display_tree(f.init_tree())
```

Next, we will need a helper function `expansion_to_children()`

that takes an expansion string and decomposes it into a list of derivation trees – one for each symbol (terminal or nonterminal) in the string. It uses the `re.split()`

method to split an expansion string into a list of children nodes:

In [46]:

```
def expansion_to_children(expansion):
# print("Converting " + repr(expansion))
# strings contains all substrings -- both terminals and nonterminals such
# that ''.join(strings) == expansion
expansion = exp_string(expansion)
assert isinstance(expansion, str)
if expansion == "": # Special case: epsilon expansion
return [("", [])]
strings = re.split(RE_NONTERMINAL, expansion)
return [(s, None) if is_nonterminal(s) else (s, [])
for s in strings if len(s) > 0]
```

In [47]:

```
expansion_to_children("<term> + <expr>")
```

Out[47]:

[('<term>', None), (' + ', []), ('<expr>', None)]

*epsilon expansion*, i.e. expanding into an empty string as in `<symbol> ::=`

needs special treatment:

In [48]:

```
expansion_to_children("")
```

Out[48]:

[('', [])]

Just like `nonterminals()`

in the chapter on Grammars, we provide for future extensions, allowing the expansion to be a tuple with extra data (which will be ignored).

In [49]:

```
expansion_to_children(("+<term>", ["extra_data"]))
```

Out[49]:

[('+', []), ('<term>', None)]

We realize this helper as a method in `GrammarFuzzer`

such that it can be overloaded by subclasses:

In [50]:

```
class GrammarFuzzer(GrammarFuzzer):
def expansion_to_children(self, expansion):
return expansion_to_children(expansion)
```

With this, we can now take some unexpanded node in the tree, choose a random expansion, and return the new tree. This is what the method `expand_node_randomly()`

does, using a helper function `choose_node_expansion()`

to randomly pick an index from an array of possible children. (`choose_node_expansion()`

can be overloaded in subclasses.)

In [52]:

```
class GrammarFuzzer(GrammarFuzzer):
def choose_node_expansion(self, node, possible_children):
"""Return index of expansion in `possible_children` to be selected. Defaults to random."""
return random.randrange(0, len(possible_children))
def expand_node_randomly(self, node):
(symbol, children) = node
assert children is None
if self.log:
print("Expanding", all_terminals(node), "randomly")
# Fetch the possible expansions from grammar...
expansions = self.grammar[symbol]
possible_children = [self.expansion_to_children(
expansion) for expansion in expansions]
# ... and select a random expansion
index = self.choose_node_expansion(node, possible_children)
chosen_children = possible_children[index]
# Process children (for subclasses)
chosen_children = self.process_chosen_children(chosen_children,
expansions[index])
# Return with new children
return (symbol, chosen_children)
```

The generic `expand_node()`

method can later be used to select different expansion strategies; as of now, it only uses `expand_node_randomly()`

.

In [53]:

```
class GrammarFuzzer(GrammarFuzzer):
def expand_node(self, node):
return self.expand_node_randomly(node)
```

`process_chosen_children()`

does nothing; it can be overloaded by subclasses to process the children once chosen.

In [54]:

```
class GrammarFuzzer(GrammarFuzzer):
def process_chosen_children(self, chosen_children, expansion):
"""Process children after selection. By default, does nothing."""
return chosen_children
```

This is how `expand_node_randomly()`

works:

In [55]:

```
f = GrammarFuzzer(EXPR_GRAMMAR, log=True)
print("Before:")
tree = ("<integer>", None)
display_tree(tree)
print("After:")
tree = f.expand_node_randomly(tree)
display_tree(tree)
```

Before:

After: Expanding <integer> randomly

Let us now apply the above node expansion to some node in the tree. To this end, we first need to search the tree for unexpanded nodes. `possible_expansions()`

counts how many unexpanded symbols there are in a tree:

In [56]:

```
class GrammarFuzzer(GrammarFuzzer):
def possible_expansions(self, node):
(symbol, children) = node
if children is None:
return 1
return sum(self.possible_expansions(c) for c in children)
```

In [57]:

```
f = GrammarFuzzer(EXPR_GRAMMAR)
print(f.possible_expansions(derivation_tree))
```

2

The method `any_possible_expansions()`

returns True if the tree has any unexpanded nodes.

In [58]:

```
class GrammarFuzzer(GrammarFuzzer):
def any_possible_expansions(self, node):
(symbol, children) = node
if children is None:
return True
return any(self.any_possible_expansions(c) for c in children)
```

In [59]:

```
f = GrammarFuzzer(EXPR_GRAMMAR)
f.any_possible_expansions(derivation_tree)
```

Out[59]:

True

Here comes `expand_tree_once()`

, the core method of our tree expansion algorithm. It first checks whether it is currently being applied on a nonterminal symbol without expansion; if so, it invokes `expand_node()`

on it, as discussed above.

If the node is already expanded (i.e. has children), it checks the subset of children which still have unexpanded symbols, randomly selects one of them, and applies itself recursively on that child.

The `expand_tree_once()`

method replaces the child *in place*, meaning that it actually mutates the tree being passed as an argument rather than returning a new tree. This in-place mutation is what makes this function particularly efficient. Again, we use a helper method (`choose_tree_expansion()`

) to return the chosen index from a list of children that can be expanded.

In [60]:

```
class GrammarFuzzer(GrammarFuzzer):
def choose_tree_expansion(self, tree, children):
"""Return index of subtree in `children` to be selected for expansion. Defaults to random."""
return random.randrange(0, len(children))
def expand_tree_once(self, tree):
"""Choose an unexpanded symbol in tree; expand it. Can be overloaded in subclasses."""
(symbol, children) = tree
if children is None:
# Expand this node
return self.expand_node(tree)
# Find all children with possible expansions
expandable_children = [
c for c in children if self.any_possible_expansions(c)]
# `index_map` translates an index in `expandable_children`
# back into the original index in `children`
index_map = [i for (i, c) in enumerate(children)
if c in expandable_children]
# Select a random child
child_to_be_expanded = \
self.choose_tree_expansion(tree, expandable_children)
# Expand in place
children[index_map[child_to_be_expanded]] = \
self.expand_tree_once(expandable_children[child_to_be_expanded])
return tree
```

Let's put it to use, expanding our derivation tree from above twice.

In [61]:

```
derivation_tree = ("<start>",
[("<expr>",
[("<expr>", None),
(" + ", []),
("<term>", None)]
)])
display_tree(derivation_tree)
```

In [62]:

```
f = GrammarFuzzer(EXPR_GRAMMAR, log=True)
derivation_tree = f.expand_tree_once(derivation_tree)
display_tree(derivation_tree)
```

Expanding <term> randomly

In [63]:

```
derivation_tree = f.expand_tree_once(derivation_tree)
display_tree(derivation_tree)
```

Expanding <term> randomly

With `expand_tree_once()`

, we can keep on expanding the tree – but how do we actually stop? The key idea here, introduced by Luke in \cite{Luke2000}, is that after inflating the derivation tree to some maximum size, we *only want to apply expansions that increase the size of the tree by a minimum*. For `<factor>`

, for instance, we would prefer an expansion into `<integer>`

, as this will not introduce further recursion (and potential size inflation); for `<integer>`

, likewise, an expansion into `<digit>`

is preferred, as it will less increase tree size than `<digit><integer>`

.

To identify the *cost* of expanding a symbol, we introduce two functions that mutually rely on each other:

`symbol_cost()`

returns the minimum cost of all expansions of a symbol, using`expansion_cost()`

to compute the cost for each expansion.`expansion_cost()`

returns the sum of all expansions in`expansions`

. If a nonterminal is encountered again during traversal, the cost of the expansion is $\infty$, indicating (potentially infinite) recursion.

In [64]:

```
class GrammarFuzzer(GrammarFuzzer):
def symbol_cost(self, symbol, seen=set()):
expansions = self.grammar[symbol]
return min(self.expansion_cost(e, seen | {symbol}) for e in expansions)
def expansion_cost(self, expansion, seen=set()):
symbols = nonterminals(expansion)
if len(symbols) == 0:
return 1 # no symbol
if any(s in seen for s in symbols):
return float('inf')
# the value of a expansion is the sum of all expandable variables
# inside + 1
return sum(self.symbol_cost(s, seen) for s in symbols) + 1
```

Here's two examples: The minimum cost of expanding a digit is 1, since we have to choose from one of its expansions.

In [65]:

```
f = GrammarFuzzer(EXPR_GRAMMAR)
assert f.symbol_cost("<digit>") == 1
```

`<expr>`

, though, is five, as this is the minimum number of expansions required. (`<expr>`

$\rightarrow$ `<term>`

$\rightarrow$ `<factor>`

$\rightarrow$ `<integer>`

$\rightarrow$ `<digit>`

$\rightarrow$ 1)

In [66]:

```
assert f.symbol_cost("<expr>") == 5
```

Here's now a variant of `expand_node()`

that takes the above cost into account. It determines the minimum cost `cost`

across all children and then chooses a child from the list using the `choose`

function, which by default is the minimum cost. If multiple children all have the same minimum cost, it chooses randomly between these.

In [67]:

```
class GrammarFuzzer(GrammarFuzzer):
def expand_node_by_cost(self, node, choose=min):
(symbol, children) = node
assert children is None
# Fetch the possible expansions from grammar...
expansions = self.grammar[symbol]
possible_children_with_cost = [(self.expansion_to_children(expansion),
self.expansion_cost(
expansion, {symbol}),
expansion)
for expansion in expansions]
costs = [cost for (child, cost, expansion)
in possible_children_with_cost]
chosen_cost = choose(costs)
children_with_chosen_cost = [child for (child, child_cost, _) in possible_children_with_cost
if child_cost == chosen_cost]
expansion_with_chosen_cost = [expansion for (_, child_cost, expansion) in possible_children_with_cost
if child_cost == chosen_cost]
index = self.choose_node_expansion(node, children_with_chosen_cost)
chosen_children = children_with_chosen_cost[index]
chosen_expansion = expansion_with_chosen_cost[index]
chosen_children = self.process_chosen_children(
chosen_children, chosen_expansion)
# Return with a new list
return (symbol, chosen_children)
```

The shortcut `expand_node_min_cost()`

passes `min()`

as the `choose`

function, which makes it expand nodes at minimum cost.

In [68]:

```
class GrammarFuzzer(GrammarFuzzer):
def expand_node_min_cost(self, node):
if self.log:
print("Expanding", all_terminals(node), "at minimum cost")
return self.expand_node_by_cost(node, min)
```

We can now apply this function to close the expansion of our derivation tree, using `expand_tree_once()`

with the above `expand_node_min_cost()`

as expansion function.

In [69]:

```
class GrammarFuzzer(GrammarFuzzer):
def expand_node(self, node):
return self.expand_node_min_cost(node)
```

In [70]:

```
f = GrammarFuzzer(EXPR_GRAMMAR, log=True)
display_tree(derivation_tree)
```

In [71]:

```
if f.any_possible_expansions(derivation_tree):
derivation_tree = f.expand_tree_once(derivation_tree)
display_tree(derivation_tree)
```

Expanding <factor> at minimum cost

In [72]:

```
if f.any_possible_expansions(derivation_tree):
derivation_tree = f.expand_tree_once(derivation_tree)
display_tree(derivation_tree)
```

Expanding <expr> at minimum cost

In [73]:

```
if f.any_possible_expansions(derivation_tree):
derivation_tree = f.expand_tree_once(derivation_tree)
display_tree(derivation_tree)
```

Expanding <term> at minimum cost

We keep on expanding until all nonterminals are expanded.

In [74]:

```
while f.any_possible_expansions(derivation_tree):
derivation_tree = f.expand_tree_once(derivation_tree)
```

Here is the final tree:

In [75]:

```
display_tree(derivation_tree)
```

We see that in each step, `expand_node_min_cost()`

chooses an expansion that does not increase the number of symbols, eventually closing all open expansions.

Especially at the beginning of an expansion, we may be interested in getting *as many nodes as possible* – that is, we'd like to prefer expansions that give us *more* nonterminals to expand. This is actually the exact opposite of what `expand_node_min_cost()`

gives us, and we can implement a method `expand_node_max_cost()`

that will always choose among the nodes with the *highest* cost:

In [76]:

```
class GrammarFuzzer(GrammarFuzzer):
def expand_node_max_cost(self, node):
if self.log:
print("Expanding", all_terminals(node), "at maximum cost")
return self.expand_node_by_cost(node, max)
```

To illustrate `expand_node_max_cost()`

, we can again redefine `expand_node()`

to use it, and then use `expand_tree_once()`

to show a few expansion steps:

In [77]:

```
class GrammarFuzzer(GrammarFuzzer):
def expand_node(self, node):
return self.expand_node_max_cost(node)
```

In [78]:

```
derivation_tree = ("<start>",
[("<expr>",
[("<expr>", None),
(" + ", []),
("<term>", None)]
)])
```

In [79]:

```
f = GrammarFuzzer(EXPR_GRAMMAR, log=True)
display_tree(derivation_tree)
```

In [80]:

```
if f.any_possible_expansions(derivation_tree):
derivation_tree = f.expand_tree_once(derivation_tree)
display_tree(derivation_tree)
```

Expanding <term> at maximum cost

In [81]:

```
if f.any_possible_expansions(derivation_tree):
derivation_tree = f.expand_tree_once(derivation_tree)
display_tree(derivation_tree)
```

Expanding <factor> at maximum cost

In [82]:

```
if f.any_possible_expansions(derivation_tree):
derivation_tree = f.expand_tree_once(derivation_tree)
display_tree(derivation_tree)
```

Expanding <expr> at maximum cost

We can now put all three phases together in a single function `expand_tree()`

which will work as follows:

**Max cost expansion.**Expand the tree using expansions with maximum cost until we have at least`min_nonterminals`

nonterminals. This phase can be easily skipped by setting`min_nonterminals`

to zero.**Random expansion.**Keep on expanding the tree randomly until we reach`max_nonterminals`

nonterminals.**Min cost expansion.**Close the expansion with minimum cost.

We implement these three phases by having `expand_node`

reference the expansion method to apply. This is controlled by setting `expand_node`

(the method reference) to first `expand_node_max_cost`

(i.e., calling `expand_node()`

invokes `expand_node_max_cost()`

), then `expand_node_randomly`

, and finally `expand_node_min_cost`

. In the first two phases, we also set a maximum limit of `min_nonterminals`

and `max_nonterminals`

, respectively.

In [83]:

```
class GrammarFuzzer(GrammarFuzzer):
def log_tree(self, tree):
"""Output a tree if self.log is set; if self.display is also set, show the tree structure"""
if self.log:
print("Tree:", all_terminals(tree))
if self.disp:
display_tree(tree)
# print(self.possible_expansions(tree), "possible expansion(s) left")
def expand_tree_with_strategy(self, tree, expand_node_method, limit=None):
"""Expand tree using `expand_node_method` as node expansion function
until the number of possible expansions reaches `limit`."""
self.expand_node = expand_node_method
while ((limit is None
or self.possible_expansions(tree) < limit)
and self.any_possible_expansions(tree)):
tree = self.expand_tree_once(tree)
self.log_tree(tree)
return tree
def expand_tree(self, tree):
"""Expand `tree` in a three-phase strategy until all expansions are complete."""
self.log_tree(tree)
tree = self.expand_tree_with_strategy(
tree, self.expand_node_max_cost, self.min_nonterminals)
tree = self.expand_tree_with_strategy(
tree, self.expand_node_randomly, self.max_nonterminals)
tree = self.expand_tree_with_strategy(
tree, self.expand_node_min_cost)
assert self.possible_expansions(tree) == 0
return tree
```

Let us try this out on our example.

In [84]:

```
derivation_tree = ("<start>",
[("<expr>",
[("<expr>", None),
(" + ", []),
("<term>", None)]
)])
f = GrammarFuzzer(
EXPR_GRAMMAR,
min_nonterminals=3,
max_nonterminals=5,
log=True)
derivation_tree = f.expand_tree(derivation_tree)
```

In [85]:

```
display_tree(derivation_tree)
```

In [86]:

```
all_terminals(derivation_tree)
```

Out[86]:

'6 - 5 + -(8) * 1 / 3'

`fuzz()`

that – like `simple_grammar_fuzzer()`

– simply takes a grammar and produces a string from it. It thus no longer exposes the complexity of derivation trees.

In [87]:

```
class GrammarFuzzer(GrammarFuzzer):
def fuzz_tree(self):
# Create an initial derivation tree
tree = self.init_tree()
# print(tree)
# Expand all nonterminals
tree = self.expand_tree(tree)
if self.log:
print(repr(all_terminals(tree)))
if self.disp:
display_tree(tree)
return tree
def fuzz(self):
self.derivation_tree = self.fuzz_tree()
return all_terminals(self.derivation_tree)
```

We can now apply this on all our defined grammars (and visualize the derivation tree along)

In [88]:

```
f = GrammarFuzzer(EXPR_GRAMMAR)
f.fuzz()
```

Out[88]:

'-3 + (46 / (8 + 8 * 0 / 5) / 2 / 2) * (++7.9) / 8 * 2 * 7'

After calling `fuzz()`

, the produced derivation tree is accessible in the `derivation_tree`

attribute:

In [89]:

```
display_tree(f.derivation_tree)
```

Let us try out the grammar fuzzer (and its trees) on other grammar formats.

In [90]:

```
f = GrammarFuzzer(URL_GRAMMAR)
f.fuzz()
```

Out[90]:

'http://user:password@fuzzingbook.com/?def=32&abc=abc'

In [91]:

```
display_tree(f.derivation_tree)
```

In [92]:

```
f = GrammarFuzzer(CGI_GRAMMAR, min_nonterminals=3, max_nonterminals=5)
f.fuzz()
```

Out[92]:

'%b0+'

In [93]:

```
display_tree(f.derivation_tree)
```

How do we stack up against `simple_grammar_fuzzer()`

?

In [94]:

```
trials = 50
xs = []
ys = []
f = GrammarFuzzer(EXPR_GRAMMAR, max_nonterminals=20)
for i in range(trials):
with Timer() as t:
s = f.fuzz()
xs.append(len(s))
ys.append(t.elapsed_time())
print(i, end=" ")
print()
```

In [95]:

```
average_time = sum(ys) / trials
print("Average time:", average_time)
```

Average time: 0.028910754639364312

In [96]:

```
%matplotlib inline
import matplotlib.pyplot as plt
plt.scatter(xs, ys)
plt.title('Time required for generating an output')
```

Out[96]:

Text(0.5,1,'Time required for generating an output')

Finally, how does `GrammarFuzzer`

work with `expr_grammar`

, where `simple_grammar_fuzzer()`

failed? It works without any issue:

In [97]:

```
f = GrammarFuzzer(expr_grammar, max_nonterminals=10)
f.fuzz()
```

Out[97]:

'(2 + 0 - 3) * (4 + 6) - 54 * 9 / 5 * 6'

`GrammarFuzzer`

, we now have a solid foundation on which to build further fuzzers and illustrate more exciting concepts from the world of generating software tests. Many of these do not even require writing a grammar – instead, they *infer* a grammar from the domain at hand, and thus allow to use grammar-based fuzzing even without writing a grammar. Stay tuned!

*Derivation trees*are important for expressing input structure*Grammar fuzzing based on derivation trees*- is much more efficient than string-based grammar fuzzing,
- gives much better control over input generation, and
- effectively avoids running into infinite expansions.

Derivation trees (then frequently called *parse trees*) are a standard data structure into which *parsers* decompose inputs. The *Dragon Book* (also known as *Compilers: Principles, Techniques, and Tools*) \cite{Aho2006} discusses parsing into derivation trees as part of compiling programs. We also use derivation trees when parsing and recombining inputs.

The key idea in this chapter, namely expanding until a limit of symbols is reached, and then always choosing the shortest path, stems from Luke \cite{Luke2000}.

Tracking `GrammarFuzzer`

reveals that some methods are called again and again, always with the same values.

Set up a class `FasterGrammarFuzzer`

with a *cache* that checks whether the method has been called before, and if so, return the previously computed "memoized" value. Do this for `expansion_to_children()`

. Compare the number of invocations before and after the optimization.

**Important**: For `expansion_to_children()`

, make sure that each list returned is an individual copy. If you return the same (cached) list, this will interfere with the in-place modification of `GrammarFuzzer`

. Use the Python `copy.deepcopy()`

function for this purpose.

Some methods such as `symbol_cost()`

or `expansion_cost()`

return a value that is dependent on the grammar only. Set up a class `EvenFasterGrammarFuzzer()`

that pre-computes these values once upon initialization, such that later invocations of `symbol_cost()`

or `expansion_cost()`

need only look up these values.

In `expand_tree_once()`

, the algorithm traverses the tree again and again to find nonterminals that still can be extended. Speed up the process by keeping a list of nonterminal symbols in the tree that still can be expanded.

`expand_node_randomly()`

such that it simply invokes `expand_node_by_cost(node, random.choice)`

:

In [109]:

```
class ExerciseGrammarFuzzer(GrammarFuzzer):
def expand_node_randomly(self, node):
if self.log:
print("Expanding", all_terminals(node), "randomly by cost")
return self.expand_node_by_cost(node, random.choice)
```

What is the difference between the original implementation and this alternative?